VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    An electron accelerated under a potential difference \[V\] volt has a certain wavelength \[\lambda \] Mass of proton is some 2000 times of the mass of the electron. If the proton has to have the same wavelength \[\lambda \] , then it will have to be accelerated under a potential difference of

    A)  \[V\text{ }volt\]

    B)  \[2000\text{ }V\text{ }volt\]

    C)  \[\frac{V}{2000}\] volt      

    D)  \[\sqrt{\text{2}000}\,V\,volt\]

    Correct Answer: C

    Solution :

    According to the question \[{{\lambda }_{e}}={{\lambda }_{p}}\] Or \[\frac{h}{\sqrt{2{{m}_{e}}{{Q}_{e}}V}}=\frac{h}{\sqrt{2{{m}_{p}}{{Q}_{p}}{{V}_{p}}}}\] \[\therefore \] \[{{m}_{e}}{{Q}_{e}}V={{m}_{p}}{{Q}_{p}}{{V}_{p}}\] \[\therefore \] \[{{V}_{p}}=\left( \frac{{{m}_{e}}}{{{m}_{p}}} \right)\left( \frac{{{Q}_{e}}}{{{Q}_{p}}} \right)V\] \[=\left( \frac{1}{2000} \right)(1)V\] \[\frac{V}{2000}volt\]


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