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VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
     In a magnetic field of 0.05 T, area of a coil changes from \[101\text{ }c{{m}^{2}}\]to \[100\,\,c{{m}^{2}}\] without changing the resistance which is\[2\Omega \]. The amount of charge that flow during this period is

    A)  \[2.5\times {{10}^{-6}}C\]

    B)  \[2\times {{10}^{-6}}C\]

    C)  \[{{10}^{-6}}C\]

    D)  \[8\times {{10}^{-6}}C\]

    Correct Answer: A

    Solution :

    \[\phi =B.A\] Change in flux \[d\phi =B.\,dA\] \[=0.05(101-100)\times {{10}^{-4}}\] \[=5\times {{10}^{-6}}Wb\] Now charge \[dQ=\frac{d\phi }{R}\] \[=\frac{5\times {{10}^{-6}}}{2}=2.5\times {{10}^{-6}}C\]


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