VIT Engineering VIT Engineering Solved Paper-2011

  • question_answer
    An electric bulb of 100 W is connected to a supply of electricity of 220 V. Resistance of the filament is

    A)  \[484\Omega \]         

    B)  \[100\Omega \]

    C)  \[22000\Omega \]

    D)  \[242\Omega \]

    Correct Answer: A

    Solution :

    The power \[P=\frac{{{V}^{2}}}{R}\] \[P=\frac{220\times 220}{100}=484\Omega \]


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