A) 1
B) 3
C) 4
D) None of these
Correct Answer: D
Solution :
We have, length of normal = c \[\Rightarrow \] \[y\sqrt{1+{{\left( \frac{dy}{dx} \right)}^{2}}}=c\] \[\Rightarrow \] \[{{y}^{2}}\left[ 1+{{\left( \frac{dy}{dx} \right)}^{2}} \right]={{c}^{2}}\] Clearly, this is the differential equation of degree 2.
You need to login to perform this action.
You will be redirected in
3 sec
