The product A is
A) succinic acid
B) melonic acid
C) oxalic acid
D) maleic acid
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{5}}I\xrightarrow[(dehydroha\log enation)]{Alc.\,\,KOH}\underset{\begin{smallmatrix} ethylene \\ X \end{smallmatrix}}{\mathop{{{C}_{2}}{{H}_{4}}}}\,\] \[\xrightarrow[CC{{l}_{4}}]{B{{r}_{2}}}\overset{Br}{\mathop{\overset{|}{\mathop{\underset{\underset{Y}{\mathop{1,\,2-dibromoethane}}\,}{\mathop{\underset{Br}{\mathop{\underset{|}{\mathop{C{{H}_{2}}C{{H}_{2}}}}\,}}\,}}\,}}\,}}\,\xrightarrow{KCN}\overset{C{{N}^{-}}}{\mathop{\underset{\begin{smallmatrix} CN \\ Z \end{smallmatrix}}{\mathop{\overset{|}{\mathop{\underset{|}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,}}\,}}\,}}\,\] \[\xrightarrow{{{H}_{3}}{{O}^{+}}}\underset{\begin{smallmatrix} succinic,\,\,acid \\ A \end{smallmatrix}}{\mathop{\overset{COOH}{\mathop{\overset{|}{\mathop{\underset{COOH}{\mathop{\underset{|}{\mathop{C{{H}_{2}}-C{{H}_{2}}}}\,}}\,}}\,}}\,}}\,\]
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