VIT Engineering VIT Engineering Solved Paper-2010

  • question_answer
    sing an AC voltmeter the potential difference in the electrical line in a house is read to be 234 V. If line frequency is known to be 50 cycles/s, the equation for the line voltage is

    A)  \[\text{V }\!\!~\!\!\text{ = 165 sin (100 }\!\!\pi\!\!\text{ t)}\]

    B)  \[\text{V=331 sin}\,\text{(100 }\!\!\pi\!\!\text{ t)}\]

    C)  \[\text{V=220}\,\text{sin}\,\text{(100 }\!\!\pi\!\!\text{ t)}\]

    D)  \[\text{V=440 sin (100 }\!\!\pi\!\!\text{ t)}\]  

    Correct Answer: B

    Solution :

    \[E={{E}_{0}}\,\,\sin \omega t\] Voltmeter read rms value \[\therefore \]   \[{{E}_{0}}=\sqrt{2}\times 234V\] \[=331V\] and \[\omega t=2\pi nt=2\pi \times 50\times t\] \[=100\pi t\] Thus, the equation of the line voltage is given  by \[E=331\,\,\sin \,(100\pi t)\]


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