A) \[{{\lambda }^{}}=\frac{\lambda }{2}\]
B) \[{{\lambda }^{}}=2\lambda \]
C) \[\frac{\lambda }{2}<{{\lambda }^{}}<\lambda \]
D) \[{{\lambda }^{}}>\lambda \]
Correct Answer: C
Solution :
\[E=\frac{hc}{\lambda }-{{W}_{0}}\] and \[2E=\frac{hc}{\lambda }-{{W}_{0}}\] \[\Rightarrow \] \[\frac{\lambda }{\lambda }=\frac{E+W}{2E+{{W}_{0}}}\] \[\Rightarrow \] \[\lambda =\lambda \left( \frac{1+{{W}_{0}}/E}{2+{{W}_{0}}/E} \right)\] Since \[\frac{(1+{{W}_{0}}/E)}{(2+{{W}_{0}}/E)}>\frac{1}{2}\] so \[\lambda >\frac{\lambda }{2}\]
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