A) \[{{2}^{n-1}}\]
B) \[{{2}^{n}}-1\]
C) \[{{2}^{n-1}}-1\]
D) \[{{2}^{n}}\]
Correct Answer: A
Solution :
The required number of ways = The even number of 0s i.e., {0, 2, 4, 6, ...} \[=\frac{n!}{n!}+\frac{n!}{2!(n-2)!}+\frac{n!}{4!(n-4)!}\] \[={}^{n}{{C}_{0}}+{}^{n}{{C}_{2}}+{}^{n}{{C}_{4}}+....={{2}^{n-1}}\]
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