VIT Engineering VIT Engineering Solved Paper-2009

  • question_answer
    Calculate \[52.15\] for the reaction, \[911\] given the following : [A] \[104\] \[52153\] [B] \[Alkyne\xrightarrow[Lindlars\,\,catalyst]{{{H}_{2}}}A\xrightarrow{Ozonolysis}\underset{only}{\mathop{B}}\,\] \[\xleftarrow[\Pr ocess]{Wac\ker }C{{H}_{2}}=C{{H}_{2}}\] [C] \[{{H}_{3}}C-C\equiv C-C{{H}_{3}}\] \[{{H}_{3}}C-C{{H}_{2}}-C\equiv CH\]

    A)  \[{{H}_{2}}C=CH-C\equiv CH\]       

    B)  \[HC\equiv C-C{{H}_{2}}-C\equiv CH\]

    C)  \[NaOH\]

    D)  \[{{104}^{o}}40\]

    Correct Answer: B

    Solution :

     By   \[2A+\frac{C}{2}-B,\] we get \[N{{a}_{2}}O+S{{O}_{3}}\xrightarrow{{}}N{{a}_{2}}S{{O}_{4}};\] \[\Delta H=-2\times 146+\frac{259}{2}-418\] or \[\Delta H=-580.5\approx -581kJ\]


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