A) \[p\pi .d\pi \]
B) \[\Delta {{H}_{f}}(H)=218kJ/mol\]
C) \[H-H\]
D) \[52.15\]
Correct Answer: C
Solution :
\[2Al+2NaOH+2{{H}_{2}}O\xrightarrow{{}}\underset{\begin{smallmatrix} sodium \\ meta \\ \text{aluminate} \end{smallmatrix}}{\mathop{2NaAl{{O}_{2}}}}\,+3{{H}_{2}}\] Sodiunimetaaluminate, thus formed, is soluble in water and changes into the complex \[{{[Al{{({{H}_{2}}O)}_{2}}{{(OH)}_{4}}]}^{-}}\], in which coordination . number of \[Al\] is 6.
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