A) \[C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}\]
B) \[{{C}_{2}}{{H}_{2}}\]
C) \[{{C}_{2}}{{H}_{6}}\]
D) \[{{C}_{2}}{{H}_{4}}\]
Correct Answer: D
Solution :
When ethyl alcohol is heated with cone \[{{H}_{2}}S{{O}_{4}}\] at \[{{160}^{o}}-{{170}^{o}}C\], the product obtained is ethylene \[({{C}_{2}}{{H}_{4}})\] \[C{{H}_{3}}-C{{H}_{2}}OH+{{H}_{2}}S{{O}_{4}}\xrightarrow{{}}\] \[\underset{ethyl\,hydrogen\,\,\sup hate}{\mathop{C{{H}_{3}}C{{H}_{2}}HS{{O}_{4}}+{{H}_{2}}O}}\,\] \[C{{H}_{3}}-C{{H}_{2}}HS{{O}_{4}}\xrightarrow[\Delta ]{160-{{170}^{o}}C}\] \[\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}+{{H}_{2}}S{{O}_{4}}}}\,\] but at lower temperature ether is formed.
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