VIT Engineering VIT Engineering Solved Paper-2008

  • question_answer
    A thin film of soap solution (n = 1.4) lies on the top of a glass plate (n = 1.5). When visible light is incident almost normal to the plate, two adjacent reflection maxima are observed at two wavelengths 400 and 630 nm. The minimum thickness of the soap solution is

    A)  420 nm       

    B)  450 nm

    C)  630 nm        

    D)  1260 nm  

    Correct Answer: B

    Solution :

    \[{{n}_{1}}{{\lambda }_{1}}={{n}_{2}}{{\lambda }_{2}}\] \[\therefore \] \[{{n}_{1}}\times 420={{n}_{2}}\times 630\] or \[2{{n}_{1}}=3{{n}_{2}}\] If \[{{n}_{2}}=2,\] then \[{{n}_{1}}=3\] Therefore, thickness of soap solution is given by \[{{\mu }_{1}}t={{n}_{1}}\frac{{{\lambda }_{1}}}{2}\] or \[t=\frac{3\times 420}{1.4\times 2}=450nm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner