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VIT Engineering VIT Engineering Solved Paper-2007

  • question_answer
    The number of real roots of the equation\[{{\left( x+\frac{1}{x} \right)}^{3}}+x+\frac{1}{x}=0\]is :

    A)  0             

    B)  2

    C)  4             

    D)  6

    Correct Answer: A

    Solution :

    \[{{\left( x+\frac{1}{x} \right)}^{3}}+\left( x+\frac{1}{x} \right)=0\] \[\Rightarrow \] \[\left( x+\frac{1}{x} \right)\left[ {{\left( x+\frac{1}{x} \right)}^{2}}+1 \right]=0\] From above it is clear that the number of real roots of given equation is 0.


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