A) circuits 2 and 3
B) circuits 1 and 2
C) circuits 1 and 3
D) none of the circuit
Correct Answer: A
Solution :
In circuit 2, each p-n junction is reverse biased, some current will flow giving equal potential difference across each p-n junction diode. In circuit 3, each p-n junction is forward biased, hence same current flows, giving same potential difference across p-n junctions.
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