A) Oxalic acid
B) Succinic acid
C) Maleic acid
D) Glutamic acid
Correct Answer: A
Solution :
Since, three membered rings are quite unstable, hence oxalic acid on heating does not form an anhydride. It decomposes to give \[C{{O}_{2}},CO\] and\[{{H}_{2}}O\]. \[\underset{COOH}{\overset{COOH}{\mathop{|}}}\,\xrightarrow[{}]{\Delta }C{{O}_{2}}+\underset{\begin{smallmatrix} \downarrow \Delta \\ CO+{{H}_{2}}O \end{smallmatrix}}{\mathop{[HCOOH]}}\,\]
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