Uttarakhand PMT Uttarakhand PMT Solved Paper-2011

  • question_answer
    An L-C resonant circuit contains a 400 pF capacitor and a 100 \[\mu H\] inductor. It is set in to oscillation coupled to an antenna. the wavelength of the radiated electromagnetic waves is

    A)  377 mm        

    B)  377 m

    C)  377 cm

    D)  3.77 cm

    Correct Answer: B

    Solution :

     Frequency of radiated electromagnetic waves \[v=\frac{1}{2\pi \sqrt{LC}}\] \[v=\frac{1}{2\pi \sqrt{100\times {{10}^{-6}}\times 400\times {{10}^{-12}}}}=\frac{{{10}^{7}}}{4\pi }Hz\] \[\therefore \]Wave length\[\lambda =\frac{c}{v}\] \[=\frac{3\times {{10}^{8}}}{{{10}^{7}}/4\pi }\] \[=120\pi \] \[\simeq 377m\]


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