A) 0.8 \[\Omega \]
B) 0.93 \[\Omega \]
C) 0.03 \[\Omega \]
D) 2.0 \[\Omega \]
Correct Answer: C
Solution :
Given, \[V=750\times {{10}^{-3}}V,\text{ }{{I}_{g}}=15\times {{10}^{-3}}A,\] and \[I=25\text{ }A\] Using the relation, \[G=\frac{V}{{{I}_{g}}}=\frac{750\times {{10}^{-3}}}{15\times {{10}^{-3}}}\] \[=50\,\Omega \] Now, from the formula, \[{{I}_{g}}=\frac{S}{S+G}\times I\] \[15\times {{10}^{-3}}=\frac{S}{S+50}\times 25\] \[\Rightarrow \] \[S=0.03\,\Omega \]
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