A) 16 : 1
B) 1 : 4
C) 12 : 1
D) 1 : 12
Correct Answer: D
Solution :
\[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{\sigma {{\Alpha }_{1}}T_{1}^{4}}{\sigma {{A}_{2}}T_{2}^{4}}\] \[\therefore \]\[\frac{{{A}_{1}}}{{{A}_{2}}}=\frac{{{p}_{1}}}{{{p}_{2}}}\times {{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}=\frac{20}{15}{{\left( \frac{500}{1000} \right)}^{4}}=\frac{1}{12}\]
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