A) 325 erg
B) 125 J
C) 250 erg
D) 250 J
Correct Answer: D
Solution :
Current \[i=\frac{100}{10}=10\,A\] \[E=\frac{1}{2}L{{I}^{2}}\] \[=\frac{1}{2}\times 5\times {{(10)}^{2}}\] \[=250\text{ }J\]
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