Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    An electron moving in a circular orbit of radius R, with a period T is equivalent to a magnetic dipole of dipole moment

    A)  \[\frac{2\pi \operatorname{Re}}{T}\]          

    B)  \[\frac{\pi eR}{T}\]

    C)  \[\frac{\pi e{{R}^{2}}}{T}\]        

    D)  \[\pi {{R}^{2}}_{e}T\]

    Correct Answer: C

    Solution :

     Dipole moment\[=iA=\frac{e}{T}.\pi {{R}^{2}}=\frac{\pi e{{R}^{2}}}{T}\]


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