Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    For an enclosure maintained at 1000 K, the maximum radiation occurs at wavelength \[{{\lambda }_{m.}}\] If the temperature is raised to 2000 K, the peak will shift to

    A)  \[{{\lambda }_{m.}}/2\]            

    B)  \[2{{\lambda }_{m.}}\]

    C)  \[{{2}^{4}}{{\lambda }_{m.}}\]            

    D)  \[{{2}^{-4}}{{\lambda }_{m.}}\]

    Correct Answer: A

    Solution :

     From Wiens displacement law, \[{{\lambda }_{m}}T=\] constant So,     \[\frac{{{({{\lambda }_{m}})}_{2}}}{{{({{\lambda }_{m}})}_{1}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[\frac{{{({{\lambda }_{m}})}_{2}}}{{{\lambda }_{m}}}=\frac{1000}{2000}\] \[\Rightarrow \] \[{{({{\lambda }_{m}})}_{2}}=\frac{{{\lambda }_{m}}}{2}\]


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