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Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    A scooter of mass 120 kg is moving with a uniform velocity of 108 km/h. The force required to stop the vehicle in 10 s is

    A)  360 N          

    B)  720 N

    C)  180 N          

    D)  \[120\times 10.8\text{ }N\]

    Correct Answer: A

    Solution :

     \[v=u+at\] \[\therefore \] \[0=\left( 108\times \frac{5}{18} \right)+a\times 10\] \[\Rightarrow \] \[0=6\times 5+a\times 10\] \[\Rightarrow \] \[a=-\frac{30}{10}=-3\,m/{{s}^{2}}\] Hence, force required \[F=ma=120\times 3=360N\]


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