Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    The transfer ratio \[\beta \] of a transistor is 50. The input resistance of the transistor when used in the common emitter mode is 1 \[K\Omega \] The peak value of the collector alternating current for an input peak voltage of 0.01V is

    A)  100 \[\mu \]A         

    B)  500 \[\mu \]A

    C)  0.01 \[\mu \]A         

    D)  0.25 \[\mu \]A

    Correct Answer: B

    Solution :

     Input current\[=\frac{{{V}_{i}}}{{{R}_{i}}}=\frac{0.01}{{{10}^{3}}}A\] \[={{10}^{-5}}A\] Output collector current \[{{i}_{c}}=\beta {{i}_{b}}=50\times {{10}^{-5}}A\] \[{{i}_{c}}=500\,\mu A\]


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