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Uttarakhand PMT Uttarakhand PMT Solved Paper-2010

  • question_answer
    If\[x=\frac{{{\varepsilon }_{0}}lv}{t}\] where \[{{\varepsilon }_{0}}\] is the permittivity of free space, v is length, v is potential difference and t is time. The dimensions of X are the same as that of

    A)  charge           

    B)  resistance

    C)  voltage          

    D)  current

    Correct Answer: D

    Solution :

     \[X=\frac{{{\varepsilon }_{0}}lV}{t}=\frac{[{{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}}][L][M{{L}^{2}}{{T}^{-3}}{{A}^{-1}}]}{[T]}\] \[[X]=[{{M}^{0}}{{L}^{0}}{{T}^{0}}A]\] which represents electric current.


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