A) \[{{(C{{H}_{3}})}_{2}}CHOH\]
B) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
C) \[C{{H}_{3}}COC{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{2}}CHO\]
Correct Answer: A
Solution :
Since, the compound evolves\[{{H}_{2}}\]on treatment with Na metal, it must contain an OH group. Further, since it gives iodoform test, therefore, it must contain the grouping \[C{{H}_{3}}CHOH-\]or\[C{{H}_{3}}CO-\]. Both these reactions are given by compound\[{{(C{{H}_{3}})}_{2}}CHOH\]or\[C{{H}_{3}}CHOHC{{H}_{3}}\].
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