A) diethylamine
B) ethylamine
C) aniline
D) methylamine
Correct Answer: A
Solution :
\[2{}^\circ \]amines (ie, diethylamine in the present case) react with\[HN{{O}_{2}}\]at low temperature to form only nitrosoamines. \[{{({{C}_{2}}{{H}_{5}})}_{2}}NH+HN{{O}_{2}}\xrightarrow[{}]{-{{H}_{2}}O}\] \[\underset{nitrosoamine}{\mathop{{{({{C}_{2}}{{H}_{5}})}_{2}}NN=O}}\,\]
You need to login to perform this action.
You will be redirected in
3 sec
