A) \[MnO_{4}^{-}\]
B) \[Cr(CN)_{6}^{3-}\]
C) \[NiF_{6}^{2-}\]
D) \[Cr{{O}_{2}}C{{l}_{2}}\]
Correct Answer: D
Solution :
Oxidation number of Cr in\[Cr{{O}_{2}}C{{l}_{2}}\]is \[x+2\times (-2)+2\times (-1)=0\] or \[x-4-2=0\]\[x=7\] or \[x=+6\] \[MnO_{4}^{-}=x+4(-2)=-1\] \[x-8=-1\] \[x=+7\] \[NiF_{6}^{2-}=x+6(-1)=-2\] \[x-6=-2\] \[x=4\] \[Cr(CN)_{6}^{3-}=x+6(-1)=-3\] \[x-6=-3,\] \[x=3\]
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