A) \[sp,\text{ }sp\]
B) \[s{{p}^{2}},\text{ }s{{p}^{2}}\]
C) \[s{{p}^{2}},\text{ }sp\]
D) \[s{{p}^{3}},\text{ }s{{p}^{2}}\]
Correct Answer: C
Solution :
In this compound carbon atoms have following hybridization: \[\overset{1}{\mathop{C}}\,{{H}_{2}}=\overset{2}{\mathop{C}}\,=C{{H}_{2}}\] \[s{{p}^{2}}\] \[sp\] Carbon one contains one \[\pi \]bond and carbon two contains two n bonds and hence, show \[s{{p}^{2}}\]and\[sp\] hybridization respectively.
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