A) 1.7
B) 1.4
C) 1.2
D) 2.7
Correct Answer: B
Solution :
From the formula, the minimum refractive index is \[{{\mu }_{m}}=\frac{\sin i}{\sin r}=\frac{\sin 90{}^\circ }{\sin 45{}^\circ }\] \[=\frac{1}{1/\sqrt{2}}\] \[=\sqrt{2}=1.414=1.4\]
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