question_answer

A tank is filled with water upto height H. When hole is made at a distance h below the level of water. What will be the horizontal range of water jet?

A)  \[2\sqrt{h(H-h)}\]    

B)  \[4\sqrt{h(H+h)}\]

C)  \[4\sqrt{h(H+h)}\]    

D)  \[2\sqrt{h(H+h)}\]

Correct Answer: A

Solution :

 Applying Bernoullis theorem, the velocity of water at point \[v=\sqrt{2gh}\] Time taken to reach point C is t So,       \[H-h=\frac{1}{2}g{{t}^{2}}\] \[t=\sqrt{\frac{2(H-h)}{g}}\] ?.(1) Now, horizontal range \[R=vt\] \[=\sqrt{2gh}\times \sqrt{\frac{2(H-h)}{g}}=2\sqrt{(H-h)h}\]