Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    The unit of second order reaction rate constant is:

    A)  \[{{L}^{-1}}.\text{ }mol.\text{ }{{s}^{-1}}\]     

    B)  \[{{L}^{2}}.\text{ }mo{{l}^{-2}}.\text{ }{{s}^{-1}}\]

    C)  \[L.\text{ }mol.\text{ }{{s}^{-1}}\].   

    D)  \[{{s}^{-1}}\]

    Correct Answer: C

    Solution :

     \[L\text{ }mo{{l}^{-1}}{{s}^{-1}}\] According to second order reaction \[2A\xrightarrow[{}]{{}}Product\] rate of reaction\[-\frac{d[A]}{dt}\propto {{[A]}^{2}}\] or \[\frac{dA}{dt}=k{{[A]}^{2}}\] \[k=\]Reaction rate constant then unit of second order reaction rate constant \[k=-\frac{d[A]}{dt}\times \frac{1}{{{[A]}^{2}}}\] \[=\frac{1}{s.mol\,{{L}^{-1}}}\]or \[L\,mo{{l}^{-1}}{{s}^{-1}}\]


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