Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    The deviation from the ideal gas behaviour of a gas can be expressed as:

    A)  \[Z=\frac{P}{VRT}\]

    B)  \[Z=\frac{PV}{nRT}\]

    C)  \[Z=\frac{nRT}{PV}\]

    D)  \[Z=\frac{VR}{PT}\]

    Correct Answer: B

    Solution :

     According to ideal gas equation \[PV=nRT\] \[n=\]Number of moles of gas then       \[\frac{PV}{nRT}=1\] Therefore the compressibility factor \[Z=\frac{PV}{nRT}=1\] for an ideal gas. For real gas Z may be either greater than one or less than one.


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