A) alkane
B) alkene
C) oxide
D) peroxide
Correct Answer: D
Solution :
The product formed by exposure of ether to oxygen and sunlight is \[\underset{Ether}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,+{{O}_{2}}\xrightarrow[{}]{sun\,light}\] \[\xrightarrow[{}]{{}}\underset{Peroxide}{\mathop{\overset{\begin{smallmatrix} O-OH \\ | \end{smallmatrix}}{\mathop{C{{H}_{3}}CH}}\,-OC{{H}_{2}}C{{H}_{3}}}}\,\]
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