Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    Rhombic and monoclinic sulphur are at equilibrium at the transition temperature\[(95.5{}^\circ C)\]. The enthalpy of transition at\[95{}^\circ C\] is\[353.8Jmo{{l}^{-1}}\]. The entropy of transition is:

    A)  \[0.46\text{ }J{{K}^{-1}}mo{{l}^{-1}}\]  

    B)  \[0.96\text{ }J{{K}^{-1}}mo{{l}^{-1}}\]

    C)  \[1.12J{{K}^{-1}}mo{{l}^{-1}}\]  

    D)  \[1.42\text{ }J{{K}^{-1}}mo{{l}^{-1}}\]

    Correct Answer: B

    Solution :

     The transition temperature \[(T)=95.5+273=368.5\text{ }K\] \[\Delta H=353.8Jmo{{l}^{-1}}\] \[\therefore \]\[\Delta S=\frac{\Delta H}{T}=\frac{353.8}{368.5}=0.96\,J{{K}^{-1}}mo{{l}^{-1}}\]


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