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Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    By adding 25 ml of\[3\text{ }M\text{ }HCl\]to 75 ml of \[0.05M\text{ }HCl,\]the molarity of\[HCl\]in the resulting solution is:

    A)  0.7875             

    B)  0.9346

    C)  1.2476            

    D)  1.6684

    Correct Answer: A

    Solution :

     We know that the molarity of resulting solution \[{{M}_{Total}}=\frac{{{M}_{1}}{{V}_{1}}}{{{V}_{Total}}}+\frac{{{M}_{2}}{{V}_{2}}}{{{V}_{Total}}}\] \[=\frac{25\times 3}{100}+\frac{75\times 0.05}{100}\] \[=0.75+0.0375\] \[=0.7875\]


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