A) \[\frac{1}{2}mg\]
B) \[\frac{1}{4}mg\]
C) \[\frac{1}{8}mg\]
D) \[\frac{1}{6}mg\]
Correct Answer: C
Solution :
We know that mass left = initial mass \[\frac{1}{2}\times \] number of half lives Here, initial mass = 1 mg, number of half lives\[=\frac{24}{8}=3\] \[\therefore \]mass left \[=1\times {{\left( \frac{1}{2} \right)}^{3}}=\frac{1}{8}mg\]
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