Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    Kinetic energy of an electron accelerated in a potential difference of 1000 volt, will be:

    A)  \[1.6\times {{10}^{-21}}\text{J}\]

    B) \[1.6\times {{10}^{-23}}\text{J}\]

    C) \[1.6\times {{10}^{-10}}\text{J}\]

    D) \[1.6\times {{10}^{-16}}\text{J}\]

    Correct Answer: D

    Solution :

     Here: Potential difference\[V=1000\text{ }volt\] The kinetic energy of an electron \[=1\,eV=1.6\times {{10}^{-19}}J\] Hence, the kinetic energy of the electron is \[=1000V\] \[=1.6\times {{10}^{-19}}\times 1000\] \[=1.6\times {{10}^{-16}}J\]


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