A) 0.48 kg m/s
B) 0.21 kg m/s
C) 9.12 kg m/s
D) none of these
Correct Answer: A
Solution :
Here: Mass of each ball \[m=0.06\text{ }kg\] Initial speed \[u=4\text{ }m/s\] final speed \[v=-4\text{ }m/s\] (minus sign implicated due to rebounce) Initial momentum of each ball before Collision is \[\mu =0.06\times 4\] \[=0.24\text{ }kg\text{ }m/s\] final momentum of each ball after collision is \[m\upsilon =0.06\times (-4)\] \[=-0.24\text{ }kg\text{ }m/sec\] Hence, the change in momentum is Initial momentum\[-\] final momentum \[=0.24-(-0.24)\] \[=0.48\text{ }kg\text{ }m/sec\]
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