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Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    A person whose nearest distance of distinct vision is 60 cm uses a reading lens of 15 cm focal length. Then the magnification will be:

    A)  5                  

    B)  3

    C)  2                   

    D)  1

    Correct Answer: A

    Solution :

     Here: Maximum distance of distinct vision \[D=60\text{ }cm\] Focal length of reading lens \[f=15\text{ }cm\] The relation for magnification is \[m=1+\frac{D}{f}\] \[=1+\frac{60}{15}=1+4=5\]


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