Uttarakhand PMT Uttarakhand PMT Solved Paper-2005

  • question_answer
    Kinetic energy of an electron in the first Bohrs orbit of the hydrogen atom is :

    A)  \[-6.5eV\]         

    B)  \[+13.6eV\]

    C)  \[-29.6\text{ }eV\]       

    D)  \[-13.6\text{ }eV\]

    Correct Answer: D

    Solution :

     As it is clear that the kinetic energy of electron in the first Bohr orbit of the hydrogen atom is given by \[K=-\frac{13.6}{{{n}^{2}}}\] \[=-\frac{13.6}{{{(1)}^{2}}}\] \[=-13.6eV\]


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