A) 50 m
B) 100 m
C) 200 m
D) 400 m
Correct Answer: B
Solution :
Here: \[u=0,\text{ }v=72\text{ }km/hr\] \[=\frac{72\times 5}{18}\] \[=20\text{ }m/s\] \[t=10\text{ }sec\] The first equation of motion is \[\upsilon =u+at\] \[20=0+a\times 10\] \[\Rightarrow \] \[a=\frac{20}{10}\] \[=2\text{ }m/{{s}^{2}}\] The second equation of motion \[s=ut+\frac{1}{2}a{{t}^{2}}\] \[=0\times 10+\frac{1}{2}\times 2\times {{(10)}^{2}}\] \[=100\text{ }m\]
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