A) \[\frac{1}{(\cos escA-\cot A)}\]
B) \[\frac{1}{(secA-tanA)}\]
C) \[\frac{1}{(secA-cosA)}\]
D) \[\frac{1}{(sinA-cosA)}\]
Correct Answer: A
Solution :
\[x=\cos ecA+\cot A\] \[=(cosecA+cotA)\frac{(cosecA-cotA)}{\cos ecA-\cot A}\] \[=\frac{\cos e{{c}^{2}}A-{{\cot }^{2}}A}{\cos ecA-\cot A}\] \[=\frac{1}{\cos ecA-\operatorname{cotA}}\]
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