A) 19 and 6
B) 34 and 21
C) 102 and 89
D) 92 and 79
Correct Answer: A
Solution :
Marks obtained by the first student \[=x\] \[\therefore \]Marks obtained by the second student \[=x+13\] According to the question, \[x+13=(x+x+13)\times \frac{76}{100}\] \[\Rightarrow \]\[x+13=(2x+13)\frac{19}{25}\] \[\Rightarrow \]\[25x+325=38x+247\] \[\Rightarrow \]\[38x-25x=325-247\] \[\Rightarrow \]\[13x=78\] \[\Rightarrow \]\[x=\frac{78}{13}=6\] \[\therefore \]Marks obtained by the second student \[=13+6=19\]
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