A) cot A
B) tan A
C) sin A
D) cos A
Correct Answer: B
Solution :
\[x=\frac{1}{\sqrt{\cos ee{{c}^{2}}A-1}}\] \[=\frac{1}{\sqrt{{{\cot }^{2}}A}}=\frac{1}{\cot A}=\tan A\]
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