A) \[6{{x}^{2}}-48x-50\]
B) \[24{{x}^{3}}+2{{x}^{2}}-32x-15\]
C) \[44{{x}^{3}}+4{{x}^{2}}-102x-25\]
D) \[24{{x}^{3}}+8{{x}^{2}}-42x-50\]
Correct Answer: C
Solution :
Expression \[={{(4x+3)}^{2}}.(3x-5)-\]\[(4{{x}^{3}}-12{{x}^{2}}+9x-20)\] \[=(16{{x}^{2}}+24x+9)(3x-5)-\]\[(4{{x}^{3}}-12{{x}^{2}}+9{{x}^{3}}-20)\] \[=(48{{x}^{3}}+72{{x}^{2}}+27x-80{{x}^{2}}\]\[120x-45)-(4{{x}^{3}}-12{{x}^{2}}+9x-20)\] \[=48{{x}^{3}}-8{{x}^{2}}-93x-45-4{{x}^{3}}+\]\[12{{x}^{2}}-9x+20\] \[=44{{x}^{3}}+4{{x}^{2}}-102x-25\]
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