A) \[\frac{-1}{\sqrt{2}}\]
B) \[\frac{2}{\sqrt{3}}\]
C) \[\frac{1}{\sqrt{2}}\]
D) \[\frac{-2}{\sqrt{3}}\]
Correct Answer: C
Solution :
\[\sin \left( -\frac{7\pi }{4} \right)=-\sin \frac{7\pi }{4}\] \[=-\sin \left( 2\pi -\frac{\pi }{4} \right)\] \[=\sin \frac{\pi }{4}=\frac{1}{\sqrt{2}}\]
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