A) \[16b{{x}^{2}}{{a}^{2}}z\]
B) \[16b{{x}^{2}}a{{z}^{2}}\]
C) \[16b{{a}^{2}}z\]
D) \[16bx{{a}^{2}}z\]
Correct Answer: B
Solution :
\[\frac{11{{b}^{3}}{{x}^{2}}{{a}^{4}}{{z}^{3}}}{7{{a}^{3}}{{b}^{2}}z}\] \[=\left( \frac{112}{7} \right)\left( \frac{{{b}^{3}}}{{{b}^{2}}} \right){{x}^{2}}.\left( \frac{{{a}^{4}}}{{{a}^{3}}} \right)\left( \frac{{{z}^{3}}}{z} \right)\] \[=16b{{x}^{2}}a{{z}^{2}}\]
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