Answer:
Given: \[u=-30\,cm,\,f=15\,cm\]
We know that, \[\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\]
\[\frac{1}{v}=\frac{1}{15}+\frac{1}{30}=\frac{2+1}{30}=\frac{3}{30}\]
\[v=\,10\,cm\]
Characteristics of image:
(i) Image formed is erect.
(ii) Image formed is small in size.
(iii) Image formed is virtual.
(iv) Image is formed at a distance of 10 cm behind the mirror between focus and pole.
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