question_answer

If a tower 30 m high, casts a shadow \[10\sqrt{3}\] long on the ground, then what is the angle of elevation of the sun?

Answer:

In \[\Delta \text{ }ABC\],

\[\tan \,\theta =\frac{AB}{BC}\]

\[\tan \,\theta =\frac{30}{10\sqrt{3}}=\sqrt{3}\]

\[\tan \,\theta =\tan \,\,60{}^\circ \,\,\,\,\,\Rightarrow \,\,\,\theta =60{}^\circ \]

Hence angle of elevation is \[60{}^\circ \]