Answer:
We have, \[{{x}^{2}}\left( \frac{a}{a+b}=\frac{a+b}{a} \right)x+1=0\] \[\Rightarrow {{x}^{2}}+\frac{a}{a+b}x+\frac{a+b}{a}x+1=0\] \[\Rightarrow \,x\left( x+\frac{a}{a+b} \right)+\frac{a+b}{a}\left( x+\frac{a}{a+b} \right)=0\] \[\Rightarrow \,\left( x+\frac{a+b}{a} \right)\left( x+\frac{a}{a+b} \right)=0\] \[\therefore x=-\frac{a}{a+b}\] or \[x=-\frac{(a+b)}{a}\]
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